7[3-(5+2x)]-2x=-16+2(1-8x)

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Solution for 7[3-(5+2x)]-2x=-16+2(1-8x) equation: 


Simplifying
7[3 + -1(5 + 2x)] + -2x = -16 + 2(1 + -8x)
7[3 + (5 * -1 + 2x * -1)] + -2x = -16 + 2(1 + -8x)
7[3 + (-5 + -2x)] + -2x = -16 + 2(1 + -8x)

Combine like terms: 3 + -5 = -2
7[-2 + -2x] + -2x = -16 + 2(1 + -8x)
[-2 * 7 + -2x * 7] + -2x = -16 + 2(1 + -8x)
[-14 + -14x] + -2x = -16 + 2(1 + -8x)

Combine like terms: -14x + -2x = -16x
-14 + -16x = -16 + 2(1 + -8x)
-14 + -16x = -16 + (1 * 2 + -8x * 2)
-14 + -16x = -16 + (2 + -16x)

Combine like terms: -16 + 2 = -14
-14 + -16x = -14 + -16x

Add '14' to each side of the equation.
-14 + 14 + -16x = -14 + 14 + -16x

Combine like terms: -14 + 14 = 0
0 + -16x = -14 + 14 + -16x
-16x = -14 + 14 + -16x

Combine like terms: -14 + 14 = 0
-16x = 0 + -16x
-16x = -16x

Add '16x' to each side of the equation.
-16x + 16x = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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